If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12^2+r^2=15^2
We move all terms to the left:
12^2+r^2-(15^2)=0
We add all the numbers together, and all the variables
r^2-81=0
a = 1; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·1·(-81)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*1}=\frac{-18}{2} =-9 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*1}=\frac{18}{2} =9 $
| x+13=-30 | | m÷10=12 | | 4x+30=-6x+50 | | 9n=3258 | | x+1–4x+8=21x= | | 2(5x−10)=65° | | -9(v+1)=2v-42 | | 2m-2m=4 | | 11x-153=89 | | x/(-3)+2=8 | | (6s+2+)(4s-2)=180 | | 8=3y−–2 | | -3+4=-6+2x | | -5(t-96)=-15 | | `p+12=7` | | x+57=160 | | -30=2(b-7)-6 | | 42=–6d | | 4m=280 | | -1=z+10 | | c+16=22 | | /6x+12=2x+28 | | /6x+12=2x+28, | | z+2=-5 | | 8`t=96 | | x+1–4x+8=21 | | 7x–12+2x+3=18 | | 14^3p=96 | | -1=p+19 | | 4^x+4*2^x-32=0 | | 180=70+(5x+13)+(4x+7) | | 3b−39=-78 |